Understanding CLR object size between 32 bit vs 64 bit

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I am trying to understand the object size difference between 32 bit and 64 bit processors. Let’s say I have a simple class

class MyClass   
{  
    int x;  
    int y;  
}  

So on a 32 bit machine, an integer is 4 bytes. If I add the Syncblock into it ( another 4 bytes), the object size will be 12 bytes. Why is it showing 16 bytes?

0:000> !do 0x029d8b98  
Name: ConsoleApplication1.Program+MyClass  
MethodTable: 000e33b0  
EEClass: 000e149c  
Size: 16(0x10) bytes  
 (C:\MyTemp\ConsoleApplication1\ConsoleApplication1\bin\x86\Debug\ConsoleApplication1.exe)  
Fields:  
      MT    Field   Offset                 Type VT     Attr    Value Name  
71972d70  4000003        4         System.Int32  1 instance        0 x  
71972d70  4000004        8         System.Int32  1 instance        0 y  

On a 64 bit machine, an integer is still 4 bytes the only thing changed is that Syncblock will be 8 bytes ( as pointers are 8 bytes on 64 bit machines). that mean the object size will be 16 bytes. Why is it showing 24 bytes?

0:000> !do 0x00000000028f3c90  
Name: ConsoleApplication1.Program+MyClass  
MethodTable: 000007ff00043af8  
EEClass: 000007ff00182408  
Size: 24(0x18) bytes  
 (C:\MyTemp\ConsoleApplication1\ConsoleApplication1\bin\Debug\ConsoleApplication1.exe)  
Fields:  
              MT    Field   Offset                 Type VT     Attr            Value Name  
000007fef4edd998  4000003        8         System.Int32  1 instance                0 x  
000007fef4edd998  4000004        c         System.Int32  1 instance                0 y  
4 Answers
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