What problem does IStructuralEquatable and IStructuralComparable solve?

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I've noticed these two interfaces, and several associated classes, have been added in .NET 4. They seem a bit superfluous to me; I've read several blogs about them, but I still can't figure out what problem they solve that was tricky before .NET 4.

What use are IStructuralEquatable and IStructuralComparable?

6 Answers

C# in a nutshell book:

Because Array is a class, arrays are always (themselves) reference types, regardless of the array’s element type. This means that the statement arrayB = arrayA results in two variables that reference the same array. Similarly, two distinct arrays will always fail an equality test—unless you use a custom equality comparer. Framework 4.0 introduced one for the purpose of comparing elements in arrays which you can access via the StructuralComparisons type.

object[] a1 = { "string", 123, true};
object[] a2 = { "string", 123, true};

Console.WriteLine(a1 == a2);               // False
Console.WriteLine(a1.Equals(a2));          // False

IStructuralEquatable se1 = a1;
Console.WriteLine(se1.Equals(a2, StructuralComparisons.StructuralEqualityComparer));    // True
Console.WriteLine(StructuralComparisons.StructuralEqualityComparer.Equals(a1, a2));     // True

object[] a3 = {"string", 123, true};
object[] a4 = {"string", 123, true};
object[] a5 = {"string", 124, true};

IStructuralComparable se2 = a3;
Console.WriteLine(se2.CompareTo(a4, StructuralComparisons.StructuralComparer));    // 0
Console.WriteLine(StructuralComparisons.StructuralComparer.Compare(a3, a4));       // 0
Console.WriteLine(StructuralComparisons.StructuralComparer.Compare(a4, a5));       // -1
Console.WriteLine(StructuralComparisons.StructuralComparer.Compare(a5, a4));       // 1

F# started using them since .net 4. ( .net 2 is here)

These interfaces are crucial to F#

let list1 = [1;5;9] 
let list2 = List.append [1;5] [9]

printfn "are they equal? %b" (list1 = list2)

list1.GetType().GetInterfaces().Dump()

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