DOS BAT file equivalent to Unix basename command?

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Is there an easy way to get to the basename (file name without extension) of a DOS file name using the DOS BAT command language?

I agree: format c:\ is probably a good start, followed by a bootable Linux CD (assuming these antique machines have a CD reader - not a given). But let's pretend that we only have DOS... (That means: not Windows - not even Windows 3.1, let alone Windows 95, 98, NT, ME, XP, Vista, 7, etc.)

8 Answers

Full-working solution (even when path contains spaces)

in .bat files

for /F "delims=" %%i in (%FILE_path%) do @echo "%%~ni"

in command-prompt use % instead of %%

(thanks to @Ciantic)

DOS 6.22 does not support %~nI in for batch statements. here's a workaround to the problem I presented in my original question about isql's 4.10 bcheck utility requiring only a basename whereas in isql 2.10 bcheck utility worked with star.star as an argument. I created the following QBASIC program to solve bcheck 4.10 now requiring only a basename to work:

BatFile$ = "CHKFILE.BAT"
        IF INSTR(COMMAND$, "?") > 0 THEN
          PRINT
          PRINT "This program generates a batch file to check Informix files"
          PRINT "  -b  BBBB.BAT    this option is used to change the batch file name"
          PRINT "                  by default the batch file name is CHKFILE.BAT"
          PRINT
          SYSTEM
        END IF
        IF INSTR(COMMAND$, "-B") > 0 THEN
          BatFile$ = LTRIM$(MID$(COMMAND$, INSTR(COMMAND$, "-B") + 2)) + "  "
          BatFile$ = LEFT$(BatFile$, INSTR(BatFile$, " ") - 1)
        END IF

        OPEN BatFile$ FOR OUTPUT AS #2


        filename$ = DIR$("*.dat")
        IF LEN(filename$) = 0 THEN SYSTEM
        DO WHILE LEN(filename$) > 0
          PRINT #2, "bcheck -y", filename$
          filename$ = DIR$
        LOOP
        CLOSE
        SYSTEM

OR, one can write an ACE program to extract the basename from systables.dirpath and PRINT "BCHECK -y ",systables.dirpath

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