JPA Criteria API - How to add JOIN clause (as general sentence as possible)

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I am trying to construct queries dynamically, and my next target is add JOIN clauses (I don't know how can I use the API).

By now, for example, this code work for me :

...
Class baseClass;   
...
CriteriaBuilder cb = JpaHandle.get().getCriteriaBuilder();
CriteriaQuery cq = cb.createQuery(this.baseClass);
Root entity_ = cq.from(this.baseClass); 
Predicate restrictions = null;
...
restrictions = cb.conjunction();
restrictions = cb.and(restrictions, entity_.get("id").in(this.listId));
...
cq.where(restrictions);
...
Query qry = JpaHandle.get().createQuery(cq);

(Note : JpaHandle is from wicket-JPA implementation)

My desire is add JOIN clause (as generical as possible)!

I have the particular annotations in the classes (this.baseClass)

For example :

@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "assay_id", nullable = false)

So,Is there a way to something like this in standard JPA ? (Note : this don't compile)

Here a practical fail aproaches :

...
Join<Experiment,Assay> experimentAssays = entity_.join( entity_.get("assay_id") );

Or like that :

...
CriteriaQuery<Customer> q = cb.createQuery(Customer.class);
Root<Customer> c = q.from(Customer.class);
SetJoin<Customer, PurchaseOrder> o = c.join(Customer_.orders);

For me, if it could be more generical as possible it will be great... :

...
Join joinClause = entity_join(entity_.get("assay_id"), entity2_.get("id"));

Of course, I have the particular annotations in the classes (this.baseClass)

Thank you for your time. I'll appreciate all kind of comments!

4 Answers
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