how to obtain all values of a multi-valued key from Django's request.GET QueryDict

user_46928 0
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The Django docs say at http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.QueryDict.iteritems thatQueryDict.iteritems() uses the same last-value logic as QueryDict.__getitem__(), which means that if the key has more than one value, __getitem__() returns the last value.

Let's say print request.GET looks like this:

<QueryDict: {u'sex': [u'1'], u'status': [u'1', u'2', u'3', u'4']}>

If I want to get a string like sex=1&status=1&status=2&status=3&status=4 (standard HTTP GET stuff) the following code won't give the desired results because of the iteritems behavior mentioned above:

mstring = []
for gk, gv in request.GET.iteritems():
    mstring.append("%s=%s" % (gk, gv))
print "&".join(mstring)

What is the most efficient way to obtain the result that I want without too much looping?

Regards.

[EDIT]

I should mention that I am not resorting to QueryDict.urlencode() because there are some keys in that request.GET that I don't want in the string. I could alter the string and take those key=value out, but just wondering if there is a better way to go about this. I realize this information should have been explicitly mentioned.

django
8 Answers

It's easy! Just print(dict(request.GET))

user_78028510

To obtain all the values from one. It's better to use getlist("key", default=list). All the values from the key is stored in a list.

request.POST.getlist('key',default=list)
user_192993450

There is a useful function in django http utils you can use:

>>> from django.utils.http import urlencode
>>> print(urlencode({"tag": [1, 2, 3], "sentence":2}, doseq=True))

'tag=1&tag=2&tag=3&sentence=2'
user_122677100
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