NSNumberFormatter and 'th' 'st' 'nd' 'rd' (ordinal) number endings

user_79307 0
Viewed 24812

Is there a way to use NSNumberFormatter to get the 'th' 'st' 'nd' 'rd' number endings?

EDIT:

Looks like it does not exist. Here's what I'm using.

+(NSString*)ordinalNumberFormat:(NSInteger)num{
    NSString *ending;

    int ones = num % 10;
    int tens = floor(num / 10);
    tens = tens % 10;
    if(tens == 1){
        ending = @"th";
    }else {
        switch (ones) {
            case 1:
                ending = @"st";
                break;
            case 2:
                ending = @"nd";
                break;
            case 3:
                ending = @"rd";
                break;
            default:
                ending = @"th";
                break;
        }
    }
    return [NSString stringWithFormat:@"%d%@", num, ending];
}

Adapted from nickf's answer here Is there an easy way in .NET to get "st", "nd", "rd" and "th" endings for numbers?

nsnumberformatter objective-c ios
21 Answers

You can try this, Its well simplified.

function numberToOrdinal(n) {

  if (n==0) {
    return n;
   }
   var j = n % 10,
       k = n % 100;


   if (j == 1 && k != 11) {
       return n + "st";
   }
   if (j == 2 && k != 12) {
       return n + "nd";
   }
   if (j == 3 && k != 13) {
       return n + "rd";
   }
   return n + "th";
}
user_109391260 
public extension Int {
 var ordinalValue: String? {
    let formatter = NumberFormatter()
    formatter.numberStyle = .ordinal
    formatter.locale = Locale(identifier: "en_US")
    return formatter.string(from: NSNumber(value: self))
 }
}

Don't forget to add the Locale, if it is not added, it won't work. Usage:

let number = 2
let ordinalNumber = number.ordinalValue
print(ordinalNumber) //It will print 2nd
user_113368400
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