Get last dirname/filename in a file path argument in Bash

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I'm trying to write a post-commit hook for SVN, which is hosted on our development server. My goal is to try to automatically checkout a copy of the committed project to the directory where it is hosted on the server. However I need to be able to read only the last directory in the directory string passed to the script in order to checkout to the same sub-directory where our projects are hosted.

For example if I make an SVN commit to the project "example", my script gets "/usr/local/svn/repos/example" as its first argument. I need to get just "example" off the end of the string and then concat it with another string so I can checkout to "/server/root/example" and see the changes live immediately.

4 Answers

To print the file name without using external commands,

Run:

fileNameWithFullPath="${fileNameWithFullPath%/}";
echo "${fileNameWithFullPath##*/}" # print the file name

This command must run faster than basename and dirname.

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