How can i select the fragment after the '#' symbol in my URL using PHP?
The result that i want is "photo45".
This is an example URL:
http://example.com/site/gallery/1#photo45
How can i select the fragment after the '#' symbol in my URL using PHP?
The result that i want is "photo45".
This is an example URL:
http://example.com/site/gallery/1#photo45
If you want to get the value after the hash mark or anchor as shown in a user's browser: This isn't possible with "standard" HTTP as this value is never sent to the server (hence it won't be available in $_SERVER["REQUEST_URI"] or similar predefined variables). You would need some sort of JavaScript magic on the client side, e.g. to include this value as a POST parameter.
If it's only about parsing a known URL from whatever source, the answer by mck89 is perfectly fine though.
That part is called "fragment" and you can get it in this way:
$url=parse_url("http://example.com/site/gallery/1#photo45 ");
echo $url["fragment"]; //This variable contains the fragment
You can't get the text after the hash mark. It is not sent to the server in a request.
https://stackoverflow.com/a/57368072/2062851
<script>
var hash = window.location.hash, //get the hash from url
cleanhash = hash.replace("#", ""); //remove the #
//alert(cleanhash);
</script>
<?php
$hash = "<script>document.writeln(cleanhash);</script>";
echo $hash;
?>
You can do it by a combination of javascript and php:
<div id="cont"></div>
And by the other side;
<script>
var h = window.location.hash;
var h1 = (win.substr(1));//string with no #
var q1 = '<input type="text" id="hash" name="hash" value="'+h1+'">';
setInterval(function(){
if(win1!="")
{
document.querySelector('#cont').innerHTML = q1;
} else alert("Something went wrong")
},1000);
</script>
Then, on form submit you can retrieve the value via $_POST['hash'] (set the form)
You need to parse the url first, so it goes like this:
$url = "https://www.example.com/profile#picture";
$fragment = parse_url($url,PHP_URL_FRAGMENT); //this variable holds the value - 'picture'
If you need to parse the actual url of the current browser, you need to request to call the server.
$url = $_SERVER["REQUEST_URI"];
$fragment = parse_url($url,PHP_URL_FRAGMENT); //this variable holds the value - 'picture'