How to assign the output of a Bash command to a variable?

user_262854 0
Viewed 364126

I have a problem putting the content of pwd command into a shell variable that I'll use later.

Here is my shell code (the loop doesn't stop):

#!/bin/bash
pwd= `pwd`
until [ $pwd = "/" ]
    do
        echo $pwd
        ls && cd .. && ls 
        $pwd= `pwd` 
    done

Could you spot my mistake, please?

shell bash
5 Answers

Try:

pwd=`pwd`

or

pwd=$(pwd)

Notice no spaces after the equals sign.

Also as Mr. Weiss points out; you don't assign to $pwd, you assign to pwd.

user_1023710

In shell you assign to a variable without the dollar-sign:

TEST=`pwd`
echo $TEST

that's better (and can be nested) but is not as portable as the backtics:

TEST=$(pwd)
echo $TEST

Always remember: the dollar-sign is only used when reading a variable.

user_559250

You can also do way more complex commands, just to round out the examples above. So, say I want to get the number of processes running on the system and store it in the ${NUM_PROCS} variable.

All you have to so is generate the command pipeline and stuff it's output (the process count) into the variable.

It looks something like this:

NUM_PROCS=$(ps -e | sed 1d | wc -l)

I hope that helps add some handy information to this discussion.

Jim_124190

Here's your script...

DIR=$(pwd)
echo $DIR
while [ "$DIR" != "/" ]; do
    cd ..
    DIR=$(pwd)
    echo $DIR
done

Note the spaces, use of quotes, and $ signs.

user_29765560
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