Assign one struct to another in C

user_265260 0
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Can you assign one instance of a struct to another, like so:

struct Test t1;
struct Test t2;
t2 = t1;

I have seen it work for simple structures, bu does it work for complex structures?
How does the compiler know how to copy data items depending on their type, i.e. differentiating between an int and string?

struct c
6 Answers

Yes if the structure is of the same type. Think it as a memory copy.

user_1216870

Yes, assignment is supported for structs. However, there are problems:

struct S {
   char * p;
};

struct S s1, s2;
s1.p = malloc(100);
s2 = s1;

Now the pointers of both structs point to the same block of memory - the compiler does not copy the pointed to data. It is now difficult to know which struct instance owns the data. This is why C++ invented the concept of user-definable assignment operators - you can write specific code to handle this case.

Admin1

This is a simple copy, just like you would do with memcpy() (indeed, some compilers actually produce a call to memcpy() for that code). There is no "string" in C, only pointers to a bunch a chars. If your source structure contains such a pointer, then the pointer gets copied, not the chars themselves.

user_2542790

Did you mean "Complex" as in complex number with real and imaginary parts? This seems unlikely, so if not you'd have to give an example since "complex" means nothing specific in terms of the C language.

You will get a direct memory copy of the structure; whether that is what you want depends on the structure. For example if the structure contains a pointer, both copies will point to the same data. This may or may not be what you want; that is down to your program design.

To perform a 'smart' copy (or a 'deep' copy), you will need to implement a function to perform the copy. This can be very difficult to achieve if the structure itself contains pointers and structures that also contain pointers, and perhaps pointers to such structures (perhaps that's what you mean by "complex"), and it is hard to maintain. The simple solution is to use C++ and implement copy constructors and assignment operators for each structure or class, then each one becomes responsible for its own copy semantics, you can use assignment syntax, and it is more easily maintained.

user_1689860

Yes, you can assign one instance of a struct to another using a simple assignment statement.

  • In the case of non-pointer or non pointer containing struct members, assignment means copy.

  • In the case of pointer struct members, assignment means pointer will point to the same address of the other pointer.

Let us see this first hand:

#include <stdio.h>

struct Test{
    int foo;
    char *bar;
};

int main(){
    struct Test t1;
    struct Test t2;
    t1.foo = 1;
    t1.bar = malloc(100 * sizeof(char));
    strcpy(t1.bar, "t1 bar value");
    t2.foo = 2;
    t2.bar = malloc(100 * sizeof(char));
    strcpy(t2.bar, "t2 bar value");
    printf("t2 foo and bar before copy: %d %s\n", t2.foo, t2.bar);
    t2 = t1;// <---- ASSIGNMENT
    printf("t2 foo and bar after copy: %d %s\n", t2.foo, t2.bar);
    //The following 3 lines of code demonstrate that foo is deep copied and bar is shallow copied
    strcpy(t1.bar, "t1 bar value changed");
    t1.foo = 3;
    printf("t2 foo and bar after t1 is altered: %d %s\n", t2.foo, t2.bar);
    return 0;
}
user_59593720
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