jqGrid dynamic column binding

user_34644 0
Viewed 68438

How to bind jqGrid dynamically?. The columns are not available at design time but will only be available only at runtime.

In the current jqGrid design the colmodels and other properties needs to be pre-populated for the grid to work correctly.

Any input in this direction is greatly appreciated.

jqgrid jquery
11 Answers

Try this in document.ready:

$.ajax(
    {
       type: "POST",
       url: "SomeUrl/GetColumnsAndData",
       data: "",
       dataType: "json",
       success: function(result)
       {
            colD = result.colData;
            colN = result.colNames;
            colM = result.colModel;

            jQuery("#list").jqGrid({
                jsonReader : {
                    cell: "",
                    id: "0"
                },
                url: 'SomeUrl/Getdata',
                datatype: 'jsonstring',
                mtype: 'POST',
                datastr : colD,
                colNames:colN,
                colModel :colM,
                pager: jQuery('#pager'),
                rowNum: 5,
                rowList: [5, 10, 20, 50],
                viewrecords: true
            })
       },
       error: function(x, e)
       {
            alert(x.readyState + " "+ x.status +" "+ e.msg);   
       }
    });
setTimeout(function() {$("#list").jqGrid('setGridParam',{datatype:'json'}); },50);

this work fine for me.

user_2538790

Is it feasible to recreate the grid each time a column is added? You could store the data locally and just Unload / Recreate the grid each time, using a dynamic column model.

You may also want to look at some of the demos that show/hide columns dynamically. Depending upon how many columns you have, you might be able to use the same concept in your application.

Does that help?

user_1012580
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