How can I increment a char?

user_209838 0
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I'm new to Python, coming from Java and C. How can I increment a char? In Java or C, chars and ints are practically interchangeable, and in certain loops, it's very useful to me to be able to do increment chars, and index arrays by chars.

How can I do this in Python? It's bad enough not having a traditional for(;;) looper - is there any way I can achieve what I want to achieve without having to rethink my entire strategy?

increment char python
7 Answers

In Python 2.x, just use the ord and chr functions:

>>> ord('c')
99
>>> ord('c') + 1
100
>>> chr(ord('c') + 1)
'd'
>>>

Python 3.x makes this more organized and interesting, due to its clear distinction between bytes and unicode. By default, a "string" is unicode, so the above works (ord receives Unicode chars and chr produces them).

But if you're interested in bytes (such as for processing some binary data stream), things are even simpler:

>>> bstr = bytes('abc', 'utf-8')
>>> bstr
b'abc'
>>> bstr[0]
97
>>> bytes([97, 98, 99])
b'abc'
>>> bytes([bstr[0] + 1, 98, 99])
b'bbc'
eliben_82060

"bad enough not having a traditional for(;;) looper"?? What?

Are you trying to do 

import string
for c in string.lowercase:
    ...do something with c...

Or perhaps you're using string.uppercase or string.letters?

Python doesn't have for(;;) because there are often better ways to do it. It also doesn't have character math because it's not necessary, either.

SLott_106610

Check this: USING FOR LOOP

for a in range(5):
    x='A'
    val=chr(ord(x) + a)
    print(val)

LOOP OUTPUT: A B C D E

user_127183530

There is a way to increase character using ascii_letters from string package which ascii_letters is a string that contains all English alphabet, uppercase and lowercase:

>>> from string import ascii_letters
>>> ascii_letters[ascii_letters.index('a') + 1]
'b'
>>> ascii_letters
'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'

Also it can be done manually;

>>> letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> letters[letters.index('c') + 1]
'd'
user_94917330 
def doubleChar(str):
    result = ''
    for char in str:
        result += char * 2
    return result

print(doubleChar("amar"))

output: 

aammaarr
user_92759990

For me i made the fallowing as a test.

string_1="abcd"

def test(string_1):
   i = 0
   p = ""
   x = len(string_1)
   while i < x:
    y = (string_1)[i]
    i=i+1
    s = chr(ord(y) + 1)
    p=p+s

   print(p)

test(string_1)
user_144498760
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