Print second-to-last column/field in `awk`

Brian_G_3208 0
Viewed 172525

I want to print the second-to-last column or field in awk. The number of fields is the NF variable. I know that I should be able to use $NF, but I'm not sure how it can be used.

And this does not seem to work:

awk ' { print ( $NF-- )  } '
awk
10 Answers
awk '{print $(NF-1)}'

Should work

user_2382420 
awk ' { print ( $(NF-1) ) }' file
user_1315270

First decrements the value and then print it -

awk ' { print $(--NF)}' file

OR

rev file|cut -d ' ' -f2|rev
user_64049490 
date
Sat Jul  9 11:57:36 EDT 2022

date | gawk '$_=$--NF'

     | mawk '$!--NF=$NF'

EDT
user_146721140
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