Is it possible to print out the size of a C++ class at compile-time?

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Is it possible to determine the size of a C++ class at compile-time?

I seem to remember a template meta-programming method, but I could be mistaken...


sorry for not being clearer - I want the size to be printed in the build output window

11 Answers

If you really need to to get sizeof(X) in the compiler output, you can use it as a parameter for an incomplete template type:

template<int s> struct Wow;
struct foo {
    int a,b;
};
Wow<sizeof(foo)> wow;

$ g++ -c test.cpp
test.cpp:5: error: aggregate ‘Wow<8> wow’ has incomplete type and cannot be defined

Whats wrong with sizeof? This should work on objects and classes.

void foo( bar* b )
{
  int i = sizeof bar;
  int j = sizeof *b;

  // please remember, that not always i==j !!!
}

Edit:

This is the example I was thinking of, but for some reason it's not working. Can anyone tell me what's wrong?

#include <iostream>
using namespace std;
class bar {
public: int i;
        bar( int ii ) { i = ii; }
        virtual ~bar(){ i = 0; }
        virtual void d() = 0;
};

class bar2: public bar {
public: long long j;
        bar2( int ii, long long jj ):bar(ii){ j=jj; }
        ~bar2() { j = 0; }
        virtual void d() { cout <<  "virtual" << endl; };
};

void foo( bar *b )
{
        int i = sizeof (bar);
        int j = sizeof *b;
        cout << "Size of bar = " << i << endl;
        cout << "Size of *b  = " << j << endl;
        b->d();
}


int main( int arcc, char *argv[] )
{
        bar2 *b = new bar2( 100, 200 );
        foo( b );
        delete b;
        return 0;
}

The application been run on linux (gcc 4.4.2):

[elcuco@pinky ~/tmp] ./sizeof_test
Size of bar = 8
Size of *b  = 8
virtual

sizeof() determines the size at compile time.

It doesn't work until compile time, so you can't use it with the preprocessor.

There is operator sizeof( int ), sizeof( char ) so I think that it is possible and call probably look like sizeof( MyClass )

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