Output an Image in PHP

user_174719 0
Viewed 149572

I have an image $file ( eg ../image.jpg )

which has a mime type $type

How can I output it to the browser?

image php
12 Answers

For the next guy or gal hitting this problem, here's what worked for me:

ob_start();
header('Content-Type: '.$mimetype);
ob_end_clean();
$fp = fopen($fullyQualifiedFilepath, 'rb');
fpassthru($fp);
exit;

You need all of that, and only that. If your mimetype varies, have a look at PHP's mime_content_type($filepath)

user_57611660

(Expanding on the accepted answer...)

I needed to:

  1. log views of a jpg image and an animated gif, and,
  2. ensure that the images are never cached (so every view is logged), and,
  3. also retain the original file extensions.

I accomplished this by creating a "secondary" .htaccess file in the sub-folder where the images are located.
The file contains only one line: 

AddHandler application/x-httpd-lsphp .jpg .jpeg .gif

In the same folder, I placed the two 'original' image files (we'll call them orig.jpg and orig.gif), as well as two variations of the [simplified] script below (saved as myimage.jpg and myimage.gif)...

<?php 
  error_reporting(0); //hide errors (displaying one would break the image)

  //get user IP and the pseudo-image's URL
  if(isset($_SERVER['REMOTE_ADDR'])) {$ip =$_SERVER['REMOTE_ADDR'];}else{$ip= '(unknown)';}
  if(isset($_SERVER['REQUEST_URI'])) {$url=$_SERVER['REQUEST_URI'];}else{$url='(unknown)';}

  //log the visit
  require_once('connect.php');            //file with db connection info
  $conn = new mysqli($servername, $username, $password, $dbname);
  if (!$conn->connect_error) {         //if connected then save mySQL record
   $conn->query("INSERT INTO imageclicks (image, ip) VALUES ('$url', '$ip');");
     $conn->close();  //(datetime is auto-added to table with default of 'now')
  } 

  //display the image
  $imgfile='orig.jpg';                             // or 'orig.gif'
  header('Content-Type: image/jpeg');              // or 'image/gif'
  header('Content-Length: '.filesize($imgfile));
  header('Cache-Control: no-cache');
  readfile($imgfile);
?>

The images render (or animate) normally and can be called in any of the normal ways for images (like an <img> tag), and will save a record of the visiting IP, while invisible to the user.

user_81127760 
header("Content-type: image/png"); 
echo file_get_contents(".../image.png");

The first step is retrieve the image from a particular location and then store it on to a variable for that purpose we use the function file_get_contents() with the destination as the parameter. Next we set the content type of the output page as image type using the header file. Finally we print the retrieved file using echo.

user_112041000
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