Remove last 3 characters of a string

user_111002 0
Viewed 501181

I'm trying to remove the last 3 characters from a string in Python, I don't know what these characters are so I can't use rstrip, I also need to remove any white space and convert to upper-case.

An example would be:

foo = "Bs12 3ab"
foo.replace(" ", "").rstrip(foo[-3:]).upper()

This works and gives me "BS12" which is what I want, however if the last 4th & 3rd characters are the same I lose both, e.g. if foo = "BS11 1AA" I just get "BS".

Examples of foo could be:

BS1 1AB
bs11ab
BS111ab

The string could be 6 or 7 characters and I need to drop the last 3 (assuming no white space).

python string
10 Answers
  1. split
  2. slice
  3. concentrate

This is a good workout for beginners and it's easy to achieve.

Another advanced method is a function like this:

def trim(s):
    return trim(s[slice])

And for this question, you just want to remove the last characters, so you can write like this:

def trim(s):
    return s[ : -3]

I think you are over to care about what those three characters are, so you lost. You just want to remove last three, nevertheless who they are!

If you want to remove some specific characters, you can add some if judgements:

def trim(s):
    if [conditions]:   ### for some cases, I recommend using isinstance().
        return trim(s[slice])
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