How do you count duplicates in a ruby array?
For example, if my array had three a's, how could I count that
How do you count duplicates in a ruby array?
For example, if my array had three a's, how could I count that
To count instances of a single element use inject
array.inject(0){|count,elem| elem == value ? count+1 : count}
arr = [1, 2, "a", "a", 4, "a", 2, 1]
arr.group_by(&:itself).transform_values(&:size)
#=> {1=>2, 2=>2, "a"=>3, 4=>1}
Ruby >= 2.7 solution here:
A new method .tally has been added.
Tallies the collection, i.e., counts the occurrences of each element. Returns a hash with the elements of the collection as keys and the corresponding counts as values.
So now, you will be able to do:
["a", "b", "c", "b"].tally #=> {"a"=>1, "b"=>2, "c"=>1}
Ruby code to get the repeated elements in the array:
numbers = [1,2,3,1,2,0,8,9,0,1,2,3]
similar = numbers.each_with_object([]) do |n, dups|
dups << n if seen.include?(n)
seen << n
end
print "similar --> ", similar
Another way to do it is to use each_with_object:
a = [ 1, 2, 3, 3, 4, 3]
hash = a.each_with_object({}) {|v, h|
h[v] ||= 0
h[v] += 1
}
# hash = { 3=>3, 2=>1, 1=>1, 4=>1 }
This way, calling a non-existing key such as hash[5] will return nil instead of 0 with Kim's solution.