Store mysql query output into a shell variable

user_89571 0
Viewed 202433

I need a variable to hold results retrieved from the database. So far this is basically what I'm trying with no success.

myvariable=$(mysql database -u $user -p $password | SELECT A, B, C FROM table_a)

My understanding of bash commands is not very good as you can see.

scripting mysql sql bash
11 Answers

Other way:

Your Script:

#!/bin/sh

# Set these variables
MyUSER="root"   # DB_USERNAME
MyPASS="yourPass"   # DB_PASSWORD
MyHOST="yourHost"    # DB_HOSTNAME
DB_NAME="dbName"
CONTAINER="containerName" #if use docker

# Get data
data=$($MyHOST -u $MyUSER -p$MyPASS $DB_NAME -h $CONTAINER -e "SELECT data1,data2 from table_name LIMIT 1;"  -B --skip-column-names)

# Set data
data1=$(echo $data | awk '{print $1}')
data2=$(echo $data | awk '{print $2}')

# Print data
echo $data1 $data2
user_112778880

Another example when the table name or database contains unsupported characters such as a space, or '-'

db='data-base'

db_d=''
db_d+='`'
db_d+=$db
db_d+='`'

myvariable=`mysql --user=$user --password=$password -e "SELECT A, B, C FROM $db_d.table_a;"`
user_28816500

My two cents here:

myvariable=$(mysql database -u $user -p$password -sse "SELECT A, B, C FROM table_a" 2>&1 \
   | grep -v "Using a password")

Removes both the column names and the annoying (but necessary) password warning. Thanks @Dominic Bartl and John for this answer.

user_11991320
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