How do I find and replace every occurrence of:
subdomainA.example.com
with
subdomainB.example.com
in every text file under the /home/www/ directory tree recursively?
How do I find and replace every occurrence of:
subdomainA.example.com
with
subdomainB.example.com
in every text file under the /home/www/ directory tree recursively?
A straight forward method if you need to exclude directories (--exclude-dir=..folder) and also might have file names with spaces (solved by using 0Byte for both grep -Z and xargs -0)
grep -rlZ oldtext . --exclude-dir=.folder | xargs -0 sed -i 's/oldtext/newtext/g'
Simplest way to replace (all files, directory, recursive)
find . -type f -not -path '*/\.*' -exec sed -i 's/foo/bar/g' {} +
Note: Sometimes you might need to ignore some hidden files i.e. .git, you can use above command.
If you want to include hidden files use,
find . -type f -exec sed -i 's/foo/bar/g' {} +
In both case the string foo will be replaced with new string bar
or use the blazing fast GNU Parallel:
grep -rl oldtext . | parallel sed -i 's/oldtext/newtext/g' {}
#!/usr/local/bin/bash -x
find * /home/www -type f | while read files
do
sedtest=$(sed -n '/^/,/$/p' "${files}" | sed -n '/subdomainA/p')
if [ "${sedtest}" ]
then
sed s'/subdomainA/subdomainB/'g "${files}" > "${files}".tmp
mv "${files}".tmp "${files}"
fi
done
Here's a version that should be more general than most; it doesn't require find (using du instead), for instance. It does require xargs, which are only found in some versions of Plan 9 (like 9front).
du -a | awk -F' ' '{ print $2 }' | xargs sed -i -e 's/subdomainA\.example\.com/subdomainB.example.com/g'
If you want to add filters like file extensions use grep:
du -a | grep "\.scala$" | awk -F' ' '{ print $2 }' | xargs sed -i -e 's/subdomainA\.example\.com/subdomainB.example.com/g'
Replacing find(1) with the simpler fd(1)/fdfind = https://github.com/sharkdp/fd:
fdfind . --type f --exec sed -i "s/original_string/new_string/g"
Addressing fd(1) iconsistent pkg & cmd names
I make an alias fdfind='fd' on macOS for consistent cmd naming (between my macOS and Linux platforms).
More on this point at https://github.com/sharkdp/fd/issues/1009.
More details and additional features
# bash examples:
1='original_string'
2='new______string'
# for this (the original-poster's) question:
1='subdomainA.example.com'
2='subdomainB.example.com'
# 'fdfind' (on at least Ubuntu 20.04) = 'fd' = https://github.com/sharkdp/fd
fdfind . --type f --exec sed -i "s/$1/$2/g"
# Here's a slightly-more-complex example that
# a. excludes (-E) .git/ and archive/ dirs, and
# b. performs a word-boundary search on the original_string (\<$1\>):
fdfind . -E .git/ -E archive/ --type f --exec sed -i "s/\<$1\>/$2/g"
Even fancier: controlling the word-boundary-ness from the third ($3) command-line paramter (third parameter = noword means no boundary, leftword means only left-side word boundary, rightword means only right-side boundary):
#!/usr/bin/env bash
#
# replace-tree.bash
#
# 'fdfind' (on at least Ubuntu 20.04) = 'fd' = https://github.com/sharkdp/fd
if [ $# -lt 2 ]; then
echo "$0: Please provide at least 2 arguments."
exit 1
fi
original="\<$1\>"
if [ "$3" = "noword" ]; then
original="$1"
elif [ "$3" = "leftword" ]; then
original="\<$1"
elif [ "$3" = "rightword" ]; then
original="$1\>"
fi
fdfind . --type f --exec sed -i "s/$original/$2/g"
Example usage:
$ replace-tree.bash original_string new_string leftword
$
I'm surprised I've not seen the simple answer using file globbing, which I just used to scan/update ONLY packge.json files with **/package.json
cd /home/www
sed -i '' -e 's/subdomainA.example.com/subdomainA.example.com/g' **/*