Programmatically get parent pid of another process?

We can use pstree command also.

pstree -p -s <pid of the process>

pstree -s gives tree of all the ancestors. Adding -p will give you the pid as well.

Example :Assume there is a process with pid=6206. Using the pstree command

pstree -p -s 6206

You will get the process tree.

systemd(1)───lightdm(1066)───lightdm(1191)───upstart(1360)───gnome-terminal-(5222)───bash(5229)───cpu-print(6206)

Here the parent PID is 5229

An easy way to craft this in pure C with only standard libraries:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAXBUF      (BUFSIZ * 2)

int pgetppid(int pid) {
    int ppid;
    char buf[MAXBUF];
    char procname[32];  // Holds /proc/4294967296/status\0
    FILE *fp;

    snprintf(procname, sizeof(procname), "/proc/%u/status", pid);
    fp = fopen(procname, "r");
    if (fp != NULL) {
        size_t ret = fread(buf, sizeof(char), MAXBUF-1, fp);
        if (!ret) {
            return 0;
        } else {
            buf[ret++] = '\0';  // Terminate it.
        }
    }
    fclose(fp);
    char *ppid_loc = strstr(buf, "\nPPid:");
    if (ppid_loc) {
        ppid = sscanf(ppid_loc, "\nPPid:%d", &ppid);
        if (!ppid || ppid == EOF) {
            return 0;
        }
        return ppid;
    } else {
        return 0;
    }

}

int main () {
    int ppid, pid = 373;  // my current cron pid
    ppid = pgetppid(pid);
    printf("PPid = %d\n", ppid);
}