long long in C/C++

user_91593 0
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I am trying this code on GNU's C++ compiler and am unable to understand its behaviour:

#include <stdio.h>;

int main()
{
    int  num1 = 1000000000;
    long num2 = 1000000000;
    long long num3;
    //num3 = 100000000000;
    long long num4 = ~0;

    printf("%u %u %u", sizeof(num1), sizeof(num2), sizeof(num3));
    printf("%d %ld %lld %llu", num1, num2, num3, num4);
    return 0;
}

When I uncomment the commented line, the code doesn't compile and is giving an error:

error: integer constant is too large for long type

But, if the code is compiled as it is and is executed, it produces values much larger than 10000000000.

Why?

long-integer c++ types
5 Answers

Note:

  1. remove semicolon after the header file
  2. use %lu instead of just %u
  3. long long num3 = 100000000000LL;

Replace these things and you are good to go :)

user_158395480
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