Normal arguments vs. keyword arguments

user_148195 0
Viewed 282639

How are "keyword arguments" different from regular arguments? Can't all arguments be passed as name=value instead of using positional syntax?

named-parameters optional-parameters arguments keyword python
10 Answers

I was looking for an example that had default kwargs using type annotation:

def test_var_kwarg(a: str, b: str='B', c: str='', **kwargs) -> str:
     return ' '.join([a, b, c, str(kwargs)])

example:

>>> print(test_var_kwarg('A', c='okay'))
A B okay {}
>>> d = {'f': 'F', 'g': 'G'}
>>> print(test_var_kwarg('a', c='c', b='b', **d))
a b c {'f': 'F', 'g': 'G'}
>>> print(test_var_kwarg('a', 'b', 'c'))
a b c {}
user_20265080

Just suplement/add a way for defining the default value of arguments that is not assigned in key words when calling the function:

def func(**keywargs):
if 'my_word' not in keywargs:
    word = 'default_msg'
else:
    word = keywargs['my_word']
return word

call this by:

print(func())
print(func(my_word='love'))

you'll get:

default_msg
love

read more about *args and **kwargs in python: https://www.digitalocean.com/community/tutorials/how-to-use-args-and-kwargs-in-python-3

user_67689940
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