How can I check the display value of an element
<tr id="pDetails" style="display:none">
$("tr[id='pDetails']").attr("style") gives me 'display:none'
I want to write a jquery script that will return me only the value of display which is 'none'
Is that possible?
Just call css with one argument
$('#idDetails').css('display');
If I understand your question. Otherwise, you want cletus' answer.
Well, for one thing your epression can be simplified:
$("#pDetails").attr("style")
since there should only be one element for any given ID and the ID selector will be much faster than the attribute id selector you're using.
If you just want to return the display value or something, use css():
$("#pDetails").css("display")
If you want to search for elements that have display none, that's a lot harder to do reliably. This is a rough example that won't be 100%:
$("[style*='display: none']")
but if you just want to find things that are hidden, use this:
$(":hidden")
If you want to check the display value, https://stackoverflow.com/a/1189281/5622596 already posted the answer.
However if instead of checking whether an element has a style of style="display:none" you want to know if that element is visible. Then use .is(":visible")
For example:
$('#idDetails').is(":visible");
This will be true if it is visible & false if it is not.
This will return what you asked, but I wouldnt recommend using css like this. Use external CSS instead of inline css.
$("tr[id='pDetails']").attr("style").split(':')[1];