A stupid way I know is:
git diff commit-number1 commit-number2
Is there a better way?
I mean, I want to know the commit1 itself. I don't want to add the commit2 before it as a parameter.
6 Answers
Does
$ git log -p
do what you need?
Check out the chapter on Git Log in the Git Community Book for more examples. (Or look at the the documentation.)
Update: As others (Jakub and Bombe) already pointed out: although the above works, git show is actually the command that is intended to do exactly what was asked for.
This is one way I know of. With git, there always seems to be more than one way to do it.
git log -p commit1 commit2
The answers by Bomber and Jakub (thanks!) are correct and work for me in different situations.
For a quick glance at what was in the commit, I use
git show <replace this with your commit-id>
But I like to view a graphical diff when studying something in detail and have set up a "P4diff" as my Git diff. I then use
git diff <replace this with your commit-id>^!
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