How to parse dates with -0400 timezone string in Python?

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I have a date string of the form '2009/05/13 19:19:30 -0400'. It seems that previous versions of Python may have supported a %z format tag in strptime for the trailing timezone specification, but 2.6.x seems to have removed that.

What's the right way to parse this string into a datetime object?

6 Answers

You can use the parse function from dateutil:

>>> from dateutil.parser import parse
>>> d = parse('2009/05/13 19:19:30 -0400')
>>> d
datetime.datetime(2009, 5, 13, 19, 19, 30, tzinfo=tzoffset(None, -14400))

This way you obtain a datetime object you can then use.

As answered, dateutil2.0 is written for Python 3.0 and does not work with Python 2.x. For Python 2.x dateutil1.5 needs to be used.

One liner for old Pythons out there. You can multiply a timedelta by 1/-1 depending on +/- sign, as in:

datetime.strptime(s[:19], '%Y-%m-%dT%H:%M:%S') + timedelta(hours=int(s[20:22]), minutes=int(s[23:])) * (-1 if s[19] == '+' else 1)

If you are on Linux, then you can use the external date command to dwim:

import commands, datetime

def parsedate(text):
  output=commands.getoutput('date -d "%s" +%%s' % text )
  try:
      stamp=eval(output)
  except:
      print output
      raise
  return datetime.datetime.frometimestamp(stamp)

This is of course less portable than dateutil, but slightly more flexible, because date will also accept inputs like "yesterday" or "last year" :-)

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