How to insert values into C# Dictionary on instantiation?

user_16508 0
Viewed 82952

Does anyone know if there is a way I can insert values into a C# Dictionary when I create it? I can, but don't want to, do dict.Add(int, "string") for each item if there is something more efficient like: 

Dictionary<int, string>(){(0, "string"),(1,"string2"),(2,"string3")};
dictionary c#
8 Answers

There's whole page about how to do that here:

http://msdn.microsoft.com/en-us/library/bb531208.aspx

Example:

In the following code example, a Dictionary<TKey, TValue> is initialized with instances of type StudentName:

var students = new Dictionary<int, StudentName>()
{
    { 111, new StudentName {FirstName="Sachin", LastName="Karnik", ID=211}},
    { 112, new StudentName {FirstName="Dina", LastName="Salimzianova", ID=317}},
    { 113, new StudentName {FirstName="Andy", LastName="Ruth", ID=198}}
};
Earwicker_274230 
Dictionary<int, string> dictionary = new Dictionary<int, string> { 
   { 0, "string" }, 
   { 1, "string2" }, 
   { 2, "string3" } };
yshuditelu_46600

You were almost there:

var dict = new Dictionary<int, string>()
{ 
   {0, "string"}, 
   {1, "string2"},
   {2, "string3"}
};
user_607610

You can also use Lambda expressions to insert any Key Value pairs from any other IEnumerable object. Key and value can be any type you want.

Dictionary<int, string> newDictionary = 
                 SomeList.ToDictionary(k => k.ID, v => v.Name);

I find that much simpler since you use the IEnumerable objects everywhere in .NET

Hope that helps!!!

Tad.

user_12005790

You can instantiate a dictionary and add items into it like this:

var dictionary = new Dictionary<int, string>
    {
        {0, "string"},
        {1, "string2"},
        {2, "string3"}
    };
user_4451050

This isn't generally recommended but in times of uncertain crises you can use

Dictionary<string, object> jsonMock = new Dictionary<string, object>() { { "object a", objA }, { "object b", objB } };

// example of unserializing
ClassForObjectA anotherObjA = null;
if(jsonMock.Contains("object a")) {
    anotherObjA = (ClassForObjA)jsonMock["object a"];
}
user_3325780
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