How do I convert an interval into a number of hours with postgres?

agnul_6069 0
Viewed 232070

Say I have an interval like

4 days 10:00:00

in postgres. How do I convert that to a number of hours (106 in this case?) Is there a function or should I bite the bullet and do something like

extract(days, my_interval) * 24 + extract(hours, my_interval)
intervals datetime postgresql
7 Answers

Probably the easiest way is:

SELECT EXTRACT(epoch FROM my_interval)/3600
user_1124990 
select floor((date_part('epoch', order_time - '2016-09-05 00:00:00') / 3600)), count(*)
from od_a_week
group by floor((date_part('epoch', order_time - '2016-09-05 00:00:00') / 3600));

The ::int conversion follows the principle of rounding. If you want a different result such as rounding down, you can use the corresponding math function such as floor.

user_62337540

I'm working with PostgreSQL 11, and I created a function to get the hours betweeen 2 differents timestamps

create function analysis.calcHours(datetime1 timestamp, datetime2 timestamp)
    returns integer
    language plpgsql as $$
    declare
        diff interval;
    begin
        diff = datetime2 - datetime1;
        return (abs(extract(days from diff))*24 + abs(extract(hours from diff)))::integer;
    end; $$;
user_58638960
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