batch parameters: everything after %1

user_38557 0
Viewed 40251

Duplicate:

Clarification: I knew of the looping approach - this worked even before Command Extensions; I was hoping for something fun and undocumented like %~*1 or whatever - just like those documented at http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/percent.mspx?mfr=true.

In a Windows batch file (with the so called "Command Extensions" on), %1 is the first argument, %2 is the second, etc. %* is all arguments concatenated.

My question: is there a way to get everything AFTER %2, for example?

I couldn't find such a thing, and it would be helpful for something I'm working on.

parameters arguments batch-file windows
7 Answers

I am not sure if there is a direct command but you can always use a simple loop and shift to get the result in a variable. Something like:

@echo off
set RESTVAR=
shift
:loop1
if "%1"=="" goto after_loop
set RESTVAR=%RESTVAR% %1
shift
goto loop1

:after_loop
echo %RESTVAR%

Let me know if it helps!

user_892560

You can use SHIFT for this. It removes %1 and shifts all other arguments one lower. This script outputs all the arguments after %2 (so it outputs %3, %4...) until one of them is empty (so it's the last one):

@echo off

SHIFT
SHIFT

:loop
if "%1" == "" goto end
echo %1
SHIFT
goto loop

:end

EDIT: Removed example using %* as this doesn't work - %* always outputs all of the parameters

schnaader_340650

Building on schnaader's answer, I think this does it if you want everything after %1 concatenated.

@echo off

SHIFT

set after1=

:loop
if "%1" == "" goto end
set after1=%after1% %1
SHIFT
goto loop


:end

echo %after1%
Scott_Langham_118980

Sebi, here's the Syntax! There is a behavior, batch eating the equal signs which is not double quoted, it cause trouble in the scripts above. If you wan't to skip, i've made a modification, based on Raman Zhylich answer and strlen.cmd:

@ECHO OFF
SETLOCAL enableDelayedExpansion

SET _tail=%*
SET "_input="
SET /A _len=0

:again
SET "_param=%1"
SET "_input=%_input%%1"
FOR /L %%i in (0,1,8191) DO IF "!_param:~%%i,1!"=="" (
    REM skip param
    SET /A _len+=%%i
    REM _len can't be use in substring
    FOR /L %%j in (!_len!,1,!_len!) DO (
        REM skip param separator
        SET /A _len+=1
        IF "!_tail:~%%j,1!"=="=" (SET "_input=%_input%=" & SHIFT & goto :again)
    )
) & goto :next
:next
IF %_len% NEQ 0 SET _tail=!_tail:~%_len%!

ENDLOCAL & SET "_input=%_input%" & SET "_tail=%_tail%"
user_52204950
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