Most efficient way to get table row count

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I currently have a database with over 6 million rows and growing. I currently do SELECT COUNT(id) FROM table; in order to display the number to my users, but the database is getting large and I have no need to store all of those rows except to be able to show the number. Is there a way to select the auto_increment value to display so that I can clear out most of the rows in the database? Using LAST_INSERT_ID() doesn't seem to work.

12 Answers

If it's only about getting the number of records (rows) I'd suggest using:

SELECT TABLE_ROWS
FROM information_schema.tables 
WHERE table_name='the_table_you_want' -- Can end here if only 1 DB 
  AND table_schema = DATABASE();      -- See comment below if > 1 DB

(at least for MySQL) instead.

try this

Execute this SQL:

SHOW TABLE STATUS LIKE '<tablename>'

and fetch the value of the field Auto_increment

if you directly get get max number by writing select query then there may chance that your query will give wrong value. e.g. if your table has 5 records so your increment id will be 6 and if I delete record no 5 the your table has 4 records with max id is 4 in this case you will get 5 as next increment id. insted to that you can get info from mysql defination itself. by writing following code in php

<?
$tablename      = "tablename";
$next_increment     = 0;
$qShowStatus        = "SHOW TABLE STATUS LIKE '$tablename'";
$qShowStatusResult  = mysql_query($qShowStatus) or die ( "Query failed: " . mysql_error() . "<br/>" . $qShowStatus );

$row = mysql_fetch_assoc($qShowStatusResult);
$next_increment = $row['Auto_increment'];

echo "next increment number: [$next_increment]";
?>

Next to the information_schema suggestion, this:

SELECT id FROM table ORDER BY id DESC LIMIT 1

should also be very fast, provided there's an index on the id field (which I believe must be the case with auto_increment)

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