Determining if a variable is within range?

Bryan_Woods_2293 0
Viewed 86602

I need to write a loop that does something like:

if i (1..10)
  do thing 1
elsif i (11..20)
  do thing 2
elsif i (21..30)
  do thing 3
etc...

But so far have gone down the wrong paths in terms of syntax.

range conditional integer ruby
10 Answers

Use the === operator (or its synonym include?)

if (1..10) === i
user_1025370

As @Baldu said, use the === operator or use case/when which internally uses === :

case i
when 1..10
  # do thing 1
when 11..20
  # do thing 2
when 21..30
  # do thing 3
etc...
user_2680

if you still wanted to use ranges...

def foo(x)
 if (1..10).include?(x)
   puts "1 to 10"
 elsif (11..20).include?(x)
   puts "11 to 20"
 end
end
user_1055360

If you need the fastest way to do it, use the good old comparing.

require 'benchmark'

i = 5
puts Benchmark.measure { 10000000.times {(1..10).include?(i)} }
puts Benchmark.measure { 10000000.times {i.between?(1, 10)}   }
puts Benchmark.measure { 10000000.times {1 <= i && i <= 10}   }

on my system prints:

0.959171   0.000728   0.959899 (  0.960447)
0.919812   0.001003   0.920815 (  0.921089)
0.340307   0.000000   0.340307 (  0.340358)

As you can see, double comparing is almost 3 times faster than #include? or #between? methods!

user_103065090

A more dynamic answer, which can be built in Ruby:

def select_f_from(collection, point) 
  collection.each do |cutoff, f|
    if point <= cutoff
      return f
    end
  end
  return nil
end

def foo(x)
  collection = [ [ 0, nil ],
                 [ 10, lambda { puts "doing thing 1"} ],
                 [ 20, lambda { puts "doing thing 2"} ],
                 [ 30, lambda { puts "doing thing 3"} ],
                 [ 40, nil ] ]

  f = select_f_from(collection, x)
  f.call if f
end

So, in this case, the "ranges" are really just fenced in with nils in order to catch the boundary conditions.

m104_40390
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