I am trying to get the difference in hours for two different Time instances. I get these values from the DB as a :datetime column
How can I do this so that it includes the months and years as well in the calculation while ignoring or rounding the minutes? Can this only be done manually or is there a function to do this?
In Rails, there is now a far more natural way to achieve this:
> past = Time.now.beginning_of_year
2018-01-01 00:00:00 +0100
> (Time.now - past) / 1.day
219.50031326506948
Rails 6.1 introduces new ActiveSupport::Duration conversion methods like in_seconds, in_minutes, in_hours, in_days, in_weeks, in_months, and in_years.
As a result, now, your problem can be solved as:
date_1 = Time.parse('2020-10-19 00:00:00 UTC')
date_2 = Time.parse('2020-10-19 03:35:38 UTC')
(date_2 - date_1).seconds.in_hours.to_i
# => 3
Here is a link to the corresponding PR.