Inline functions in C#?

Inline methods are simply a compiler optimization where the code of a function is rolled into the caller.

There's no mechanism by which to do this in C#, and they're to be used sparingly in languages where they are supported -- if you don't know why they should be used somewhere, they shouldn't be.

Edit: To clarify, there are two major reasons they need to be used sparingly:

1. It's easy to make massive binaries by using inline in cases where it's not necessary
2. The compiler tends to know better than you do when something should, from a performance standpoint, be inlined

It's best to leave things alone and let the compiler do its work, then profile and figure out if inline is the best solution for you. Of course, some things just make sense to be inlined (mathematical operators particularly), but letting the compiler handle it is typically the best practice.

Update: Per konrad.kruczynski's answer, the following is true for versions of .NET up to and including 4.0.

You can use the MethodImplAttribute class to prevent a method from being inlined...

[MethodImpl(MethodImplOptions.NoInlining)]
void SomeMethod()
{
    // ...
}

...but there is no way to do the opposite and force it to be inlined.

You're mixing up two separate concepts. Function inlining is a compiler optimization which has no impact on the semantics. A function behaves the same whether it's inlined or not.

On the other hand, lambda functions are purely a semantic concept. There is no requirement on how they should be implemented or executed, as long as they follow the behavior set out in the language spec. They can be inlined if the JIT compiler feels like it, or not if it doesn't.

There is no inline keyword in C#, because it's an optimization that can usually be left to the compiler, especially in JIT'ed languages. The JIT compiler has access to runtime statistics which enables it to decide what to inline much more efficiently than you can when writing the code. A function will be inlined if the compiler decides to, and there's nothing you can do about it either way. :)

Cody has it right, but I want to provide an example of what an inline function is.

Let's say you have this code:

private void OutputItem(string x)
{
    Console.WriteLine(x);

    //maybe encapsulate additional logic to decide 
    // whether to also write the message to Trace or a log file
}

public IList<string> BuildListAndOutput(IEnumerable<string> x)
{  // let's pretend IEnumerable<T>.ToList() doesn't exist for the moment
    IList<string> result = new List<string>();

    foreach(string y in x)
    {
        result.Add(y);
        OutputItem(y);
    }
    return result;
}

The compilerJust-In-Time optimizer could choose to alter the code to avoid repeatedly placing a call to OutputItem() on the stack, so that it would be as if you had written the code like this instead:

public IList<string> BuildListAndOutput(IEnumerable<string> x)
{
    IList<string> result = new List<string>();

    foreach(string y in x)
    {
        result.Add(y);

        // full OutputItem() implementation is placed here
        Console.WriteLine(y);   
    }

    return result;
}

In this case, we would say the OutputItem() function was inlined. Note that it might do this even if the OutputItem() is called from other places as well.

Edited to show a scenario more-likely to be inlined.

Do you mean inline functions in the C++ sense? In which the contents of a normal function are automatically copied inline into the callsite? The end effect being that no function call actually happens when calling a function.

Example:

inline int Add(int left, int right) { return left + right; }

If so then no, there is no C# equivalent to this.

Or Do you mean functions that are declared within another function? If so then yes, C# supports this via anonymous methods or lambda expressions.

Example:

static void Example() {
  Func<int,int,int> add = (x,y) => x + y;
  var result = add(4,6);  // 10
}

Yes Exactly, the only distinction is the fact it returns a value.

Simplification (not using expressions):

List<T>.ForEach Takes an action, it doesn't expect a return result.

So an Action<T> delegate would suffice.. say:

List<T>.ForEach(param => Console.WriteLine(param));

is the same as saying:

List<T>.ForEach(delegate(T param) { Console.WriteLine(param); });

the difference is that the param type and delegate decleration are inferred by usage and the braces aren't required on a simple inline method.

Where as

List<T>.Where Takes a function, expecting a result.

So an Function<T, bool> would be expected:

List<T>.Where(param => param.Value == SomeExpectedComparison);

which is the same as:

List<T>.Where(delegate(T param) { return param.Value == SomeExpectedComparison; });

You can also declare these methods inline and asign them to variables IE:

Action myAction = () => Console.WriteLine("I'm doing something Nifty!");

myAction();

or

Function<object, string> myFunction = theObject => theObject.ToString();

string myString = myFunction(someObject);

I hope this helps.

No, there is no such construct in C#, but the .NET JIT compiler could decide to do inline function calls on JIT time. But i actually don't know if it is really doing such optimizations.
(I think it should :-))

Lambda expressions are inline functions! I think, that C# doesn`t have a extra attribute like inline or something like that!

C# does not support inline methods (or functions) in the way dynamic languages like python do. However anonymous methods and lambdas can be used for similar purposes including when you need to access a variable in the containing method like in the example below.

static void Main(string[] args)
{
    int a = 1;

    Action inline = () => a++;
    inline();
    //here a = 2
}