How do you left pad an int with zeros when converting to a String in java?
I'm basically looking to pad out integers up to 9999 with leading zeros (e.g. 1 = 0001).
How do you left pad an int with zeros when converting to a String in java?
I'm basically looking to pad out integers up to 9999 with leading zeros (e.g. 1 = 0001).
Use java.lang.String.format(String,Object...) like this:
String.format("%05d", yournumber);
for zero-padding with a length of 5. For hexadecimal output replace the d with an x as in "%05x".
The full formatting options are documented as part of java.util.Formatter.
If you for any reason use pre 1.5 Java then may try with Apache Commons Lang method
org.apache.commons.lang.StringUtils.leftPad(String str, int size, '0')
Found this example... Will test...
import java.text.DecimalFormat;
class TestingAndQualityAssuranceDepartment
{
public static void main(String [] args)
{
int x=1;
DecimalFormat df = new DecimalFormat("00");
System.out.println(df.format(x));
}
}
Tested this and:
String.format("%05d",number);
Both work, for my purposes I think String.Format is better and more succinct.
Try this one:
import java.text.DecimalFormat;
DecimalFormat df = new DecimalFormat("0000");
String c = df.format(9); // Output: 0009
String a = df.format(99); // Output: 0099
String b = df.format(999); // Output: 0999
Here is how you can format your string without using DecimalFormat.
String.format("%02d", 9)
09
String.format("%03d", 19)
019
String.format("%04d", 119)
0119
You need to use a Formatter, following code uses NumberFormat
int inputNo = 1;
NumberFormat nf = NumberFormat.getInstance();
nf.setMaximumIntegerDigits(4);
nf.setMinimumIntegerDigits(4);
nf.setGroupingUsed(false);
System.out.println("Formatted Integer : " + nf.format(inputNo));
Output: 0001
Use the class DecimalFormat, like so:
NumberFormat formatter = new DecimalFormat("0000"); //i use 4 Zero but you can also another number
System.out.println("OUTPUT : "+formatter.format(811));
OUTPUT : 0000811
You can add leading 0 to your string like this. Define a string that will be the maximum length of the string that you want. In my case i need a string that will be only 9 char long.
String d = "602939";
d = "000000000".substring(0, (9-d.length())) + d;
System.out.println(d);
Output : 000602939
Use this simple extension function
fun Int.padZero(): String {
return if (this < 10) {
"0$this"
} else {
this.toString()
}
}
For Kotlin
fun Calendar.getFullDate(): String {
val mYear = "${this.get(Calendar.YEAR)}-"
val mMonth = if (this.get(Calendar.MONTH) + 1 < 10) {
"0${this.get(Calendar.MONTH) + 1}-"
} else {
"${this.get(Calendar.MONTH)+ 1}-"
}
val mDate = if (this.get(Calendar.DAY_OF_MONTH) < 10) {
"0${this.get(Calendar.DAY_OF_MONTH)}"
} else {
"${this.get(Calendar.DAY_OF_MONTH)}"
}
return mYear + mMonth + mDate
}
and use it as
val date: String = calendar.getFullDate()
Here is another way to pad an integer with zeros on the left. You can increase the number of zeros as per your convenience. Have added a check to return the same value as is in case of negative number or a value greater than or equals to zeros configured. You can further modify as per your requirement.
/**
*
* @author Dinesh.Lomte
*
*/
public class AddLeadingZerosToNum {
/**
*
* @param args
*/
public static void main(String[] args) {
System.out.println(getLeadingZerosToNum(0));
System.out.println(getLeadingZerosToNum(7));
System.out.println(getLeadingZerosToNum(13));
System.out.println(getLeadingZerosToNum(713));
System.out.println(getLeadingZerosToNum(7013));
System.out.println(getLeadingZerosToNum(9999));
}
/**
*
* @param num
* @return
*/
private static String getLeadingZerosToNum(int num) {
// Initializing the string of zeros with required size
String zeros = new String("0000");
// Validating if num value is less then zero or if the length of number
// is greater then zeros configured to return the num value as is
if (num < 0 || String.valueOf(num).length() >= zeros.length()) {
return String.valueOf(num);
}
// Returning zeros in case if value is zero.
if (num == 0) {
return zeros;
}
return new StringBuilder(zeros.substring(0, zeros.length() -
String.valueOf(num).length())).append(
String.valueOf(num)).toString();
}
}
Input
0
7
13
713
7013
9999
Output
0000
0007
0013
7013
9999