GetProperties() to return all properties for an interface inheritance hierarchy

sduplooy_31770 0
Viewed 53290

Assuming the following hypothetical inheritance hierarchy:

public interface IA
{
  int ID { get; set; }
}

public interface IB : IA
{
  string Name { get; set; }
}

Using reflection and making the following call: 

typeof(IB).GetProperties(BindingFlags.Public | BindingFlags.Instance)

will only yield the properties of interface IB, which is "Name".

If we were to do a similar test on the following code,

public abstract class A
{
  public int ID { get; set; }
}

public class B : A
{
  public string Name { get; set; }
}

the call typeof(B).GetProperties(BindingFlags.Public | BindingFlags.Instance) will return an array of PropertyInfo objects for "ID" and "Name".

Is there an easy way to find all the properties in the inheritance hierarchy for interfaces as in the first example?

reflection .net c#
6 Answers

I've tweaked @Marc Gravel's example code into a useful extension method encapsulates both classes and interfaces. It also add's the interface properties first which I believe is the expected behaviour.

public static PropertyInfo[] GetPublicProperties(this Type type)
{
    if (type.IsInterface)
    {
        var propertyInfos = new List<PropertyInfo>();

        var considered = new List<Type>();
        var queue = new Queue<Type>();
        considered.Add(type);
        queue.Enqueue(type);
        while (queue.Count > 0)
        {
            var subType = queue.Dequeue();
            foreach (var subInterface in subType.GetInterfaces())
            {
                if (considered.Contains(subInterface)) continue;

                considered.Add(subInterface);
                queue.Enqueue(subInterface);
            }

            var typeProperties = subType.GetProperties(
                BindingFlags.FlattenHierarchy 
                | BindingFlags.Public 
                | BindingFlags.Instance);

            var newPropertyInfos = typeProperties
                .Where(x => !propertyInfos.Contains(x));

            propertyInfos.InsertRange(0, newPropertyInfos);
        }

        return propertyInfos.ToArray();
    }

    return type.GetProperties(BindingFlags.FlattenHierarchy
        | BindingFlags.Public | BindingFlags.Instance);
}
user_857850

Interface hierarchies are a pain - they don't really "inherit" as such, since you can have multiple "parents" (for want of a better term).

"Flattening" (again, not quite the right term) the hierarchy might involve checking for all the interfaces that the interface implements and working from there...

interface ILow { void Low();}
interface IFoo : ILow { void Foo();}
interface IBar { void Bar();}
interface ITest : IFoo, IBar { void Test();}

static class Program
{
    static void Main()
    {
        List<Type> considered = new List<Type>();
        Queue<Type> queue = new Queue<Type>();
        considered.Add(typeof(ITest));
        queue.Enqueue(typeof(ITest));
        while (queue.Count > 0)
        {
            Type type = queue.Dequeue();
            Console.WriteLine("Considering " + type.Name);
            foreach (Type tmp in type.GetInterfaces())
            {
                if (!considered.Contains(tmp))
                {
                    considered.Add(tmp);
                    queue.Enqueue(tmp);
                }
            }
            foreach (var member in type.GetMembers())
            {
                Console.WriteLine(member.Name);
            }
        }
    }
}
Marc_Gravell_233540

Exactly the same problem has a workaround described here.

FlattenHierarchy doesnt work btw. (only on static vars. says so in intellisense)

Workaround. Beware of duplicates.

PropertyInfo[] pis = typeof(IB).GetProperties(BindingFlags.Public | BindingFlags.Instance);
Type[] tt = typeof(IB).GetInterfaces();
PropertyInfo[] pis2 = tt[0].GetProperties(BindingFlags.Public | BindingFlags.Instance);
Wolf5_376430

Responding to @douglas and @user3524983, the following should answer the OP's question: 

    static public IEnumerable<PropertyInfo> GetPropertiesAndInterfaceProperties(this Type type, BindingFlags bindingAttr = BindingFlags.Public | BindingFlags.Instance)
    {
        if (!type.IsInterface) {
            return type.GetProperties( bindingAttr);
        }

        return type.GetInterfaces().Union(new Type[] { type }).SelectMany(i => i.GetProperties(bindingAttr)).Distinct();
    }

or, for an individual property: 

    static public PropertyInfo GetPropertyOrInterfaceProperty(this Type type, string propertyName, BindingFlags bindingAttr = BindingFlags.Public|BindingFlags.Instance)
    {
        if (!type.IsInterface) {
            return type.GetProperty(propertyName, bindingAttr);
        }

        return type.GetInterfaces().Union(new Type[] { type }).Select(i => i.GetProperty( propertyName, bindingAttr)).Distinct().Where(propertyInfo => propertyInfo != null).Single();
    }

OK next time I'll debug it before posting instead of after :-)

user_60908280
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