Removing duplicate rows in vi?

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I have a text file that contains a long list of entries (one on each line). Some of these are duplicates, and I would like to know if it is possible (and if so, how) to remove any duplicates. I am interested in doing this from within vi/vim, if possible.

14 Answers

If you're OK with sorting your file, you can use:

:sort u

Try this:

:%s/^\(.*\)\(\n\1\)\+$/\1/

It searches for any line immediately followed by one or more copies of itself, and replaces it with a single copy.

Make a copy of your file though before you try it. It's untested.

I would combine two of the answers above:

go to head of file
sort the whole file
remove duplicate entries with uniq

1G
!Gsort
1G
!Guniq

If you were interested in seeing how many duplicate lines were removed, use control-G before and after to check on the number of lines present in your buffer.

Select the lines in visual-line mode (Shift+v), then :!uniq. That'll only catch duplicates which come one after another.

If you don't want to sort/uniq the entire file, you can select the lines you want to make uniq in visual mode and then simply: :sort u.

Regarding how Uniq can be implemented in VimL, search for Uniq in a plugin I'm maintaining. You'll see various ways to implement it that were given on Vim mailing-list.

Otherwise, :sort u is indeed the way to go.

I would use !}uniq, but that only works if there are no blank lines.

For every line in a file use: :1,$!uniq.

An alternative method that does not use vi/vim (for very large files), is from the Linux command line use sort and uniq:

sort {file-name} | uniq -u

This worked for me for both .csv and .txt

awk '!seen[$0]++' <filename> > <newFileName>

Explanation: The first part of the command prints unique rows and the second part i.e. after the middle arrow is to save the output of the first part.

awk '!seen[$0]++' <filename>

>

<newFileName>

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