Rounding a number to the nearest 5 or 10 or X

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Given numbers like 499, 73433, 2348 what VBA can I use to round to the nearest 5 or 10? or an arbitrary number?

By 5:

 499 ->  500
2348 -> 2350
7343 -> 7345

By 10:

 499 ->  500
2348 -> 2350
7343 -> 7340

etc.

13 Answers

It's simple math. Given a number X and a rounding factor N, the formula would be:

round(X / N)*N

To round to the nearest X (without being VBA specific)

N = X * int(N / X + 0.5)

Where int(...) returns the next lowest whole number.

If your available rounding function already rounds to the nearest whole number then omit the addition of 0.5

For a strict Visual Basic approach, you can convert the floating-point value to an integer to round to said integer. VB is one of the rare languages that rounds on type conversion (most others simply truncate.)

Multiples of 5 or x can be done simply by dividing before and multiplying after the round.

If you want to round and keep decimal places, Math.round(n, d) would work.

something like that?

'nearest
 n = 5
 'n = 10

 'value
 v = 496
 'v = 499 
 'v = 2348 
 'v = 7343

 'mod
 m = (v \ n) * n

 'diff between mod and the val
 i = v-m


 if i >= (n/2) then     
      msgbox m+n
 else
      msgbox m
 end if

I cannot add comment so I will use this

in a vbs run that and have fun figuring out why the 2 give a result of 2

you can't trust round

 msgbox round(1.5) 'result to 2
 msgbox round(2.5) 'yes, result to 2 too

Try this function

--------------start----------------

Function Round_Up(ByVal d As Double) As Integer
    Dim result As Integer
    result = Math.Round(d)
    If result >= d Then
        Round_Up = result
    Else
        Round_Up = result + 1
    End If
End Function

-------------end ------------

I slightly updated the function provided by the "community wiki" (the best answer), just to round to the nearest 5 (or anything you like), with this exception : the rounded number will NEVER be superior to the original number.

This is useful in cases when it is needed to say that "a company is alive for 47 years" : I want the web page to display "is alive for more than 45 years", while avoiding lying in stating "is alive for more than 50 years".

So when you feed this function with 47, it will not return 50, but will return 45 instead.

'Rounds a number to the nearest unit, never exceeding the actual value
function RoundToNearestOrBelow(num, r)

    '@param         num         Long/Integer/Double     The number to be rounded
    '@param         r           Long                    The rounding value
    '@return        OUT         Long                    The rounded value

    'Example usage :
    '   Round 47 to the nearest 5 : it will return 45
    '   Response.Write RoundToNearestBelow(47, 5)

    Dim OUT : OUT = num

    Dim rounded : rounded = Round((((num)) / r), 0) * r

    if (rounded =< num) then
        OUT = rounded
    else
        OUT = rounded - r
    end if

    'Return
    RoundToNearestOrBelow = OUT

end function 'RoundToNearestOrBelow
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