Generating an array of letters in the alphabet

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Is there an easy way to generate an array containing the letters of the alphabet in C#? It's not too hard to do it by hand, but I was wondering if there was a built in way to do this.

14 Answers

I don't think there is a built in way, but I think the easiest would be

  char[] alpha = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

C# 3.0 :

char[] az = Enumerable.Range('a', 'z' - 'a' + 1).Select(i => (Char)i).ToArray();
foreach (var c in az)
{
    Console.WriteLine(c);
}

yes it does work even if the only overload of Enumerable.Range accepts int parameters ;-)

Assuming you mean the letters of the English alphabet...

    for ( int i = 0; i < 26; i++ )
    {
        Console.WriteLine( Convert.ToChar( i + 65 ) );
    }
    Console.WriteLine( "Press any key to continue." );
    Console.ReadKey();

You could do something like this, based on the ascii values of the characters:

char[26] alphabet;

for(int i = 0; i <26; i++)
{
     alphabet[i] = (char)(i+65); //65 is the offset for capital A in the ascaii table
}

(See the table here.) You are just casting from the int value of the character to the character value - but, that only works for ascii characters not different languages etc.

EDIT: As suggested by Mehrdad in the comment to a similar solution, it's better to do this:

alphabet[i] = (char)(i+(int)('A'));

This casts the A character to it's int value and then increments based on this, so it's not hardcoded.

Note also, the string has a operator[] which returns a Char, and is an IEnumerable<char>, so for most purposes, you can use a string as a char[]. Hence:

string alpha = "ABCDEFGHIJKLMNOPQRSTUVQXYZ";
for (int i =0; i < 26; ++i)
{  
     Console.WriteLine(alpha[i]);
}

foreach(char c in alpha)
{  
     Console.WriteLine(c);
}
var alphabets = Enumerable.Range('A', 26).Select((num) => ((char)num).ToString()).ToList();

4 ways get English alphabet in Console:

public void ShowEnglishAlphabet()
{
    var firstLetter = 'a';
    var endLetter = 'z';
    for (var letter = firstLetter; letter <= endLetter; letter++)
    {
        Console.WriteLine($"{letter}-{letter.ToString().ToUpper()}");
    }
}

public void ShowEnglishAlphabetFromUnicodeTableDecNumber()
{
    var firstLetter = 97;
    var endLetter = 122;
    for (var letterNumberUnicodeTable = firstLetter; 
    letterNumberUnicodeTable <= endLetter; letterNumberUnicodeTable++)
    {
        Console.WriteLine($"{(char)letterNumberUnicodeTable}- 
        {((char)letterNumberUnicodeTable).ToString().ToUpper()}");
    }
}

public void ShowEnglishAlphabetUnicodeTableEscapeSequence()
{
    var firstLetter = '\u0061';
    var endLetter = '\u007A';
    for (var letterNumberUnicodeTable = firstLetter; 
    letterNumberUnicodeTable <= endLetter; letterNumberUnicodeTable++)
    {
        Console.WriteLine($"{letterNumberUnicodeTable}- 
        {letterNumberUnicodeTable.ToString().ToUpper()}");
    }
}   

public void ShowEnglishAlphabetUnicodeTableLinq()
{
    var alphabets = Enumerable.Range('a', 26).Select(letter => 
    ((char)letter).ToString()).ToList();
    foreach (var letter in alphabets)
    {
        Console.WriteLine($"{letter}-{letter.ToUpper()}");
    }
}

Unfortunately there is no ready-to-use way.

You can use; char[] characters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

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