Play a Sound with Python

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What's the easiest way to play a sound file (.wav) in Python? By easiest I mean both most platform independent and requiring the least dependencies. pygame is certainly an option, but it seems overkill for just sound.

10 Answers

For Windows, you can use winsound. It's built in

import winsound

winsound.PlaySound('sound.wav', winsound.SND_FILENAME)

You should be able to use ossaudiodev for linux:

from wave import open as waveOpen
from ossaudiodev import open as ossOpen
s = waveOpen('tada.wav','rb')
(nc,sw,fr,nf,comptype, compname) = s.getparams( )
dsp = ossOpen('/dev/dsp','w')
try:
  from ossaudiodev import AFMT_S16_NE
except ImportError:
  from sys import byteorder
  if byteorder == "little":
    AFMT_S16_NE = ossaudiodev.AFMT_S16_LE
  else:
    AFMT_S16_NE = ossaudiodev.AFMT_S16_BE
dsp.setparameters(AFMT_S16_NE, nc, fr)
data = s.readframes(nf)
s.close()
dsp.write(data)
dsp.close()

(Credit for ossaudiodev: Bill Dandreta http://mail.python.org/pipermail/python-list/2004-October/288905.html)

Definitely use Pyglet for this. It's kind of a large package, but it is pure python with no extension modules. That will definitely be the easiest for deployment. It's also got great format and codec support.

import pyglet

music = pyglet.resource.media('music.mp3')
music.play()

pyglet.app.run()

pyMedia's sound example does just that. This should be all you need.

import time, wave, pymedia.audio.sound as sound
f= wave.open( 'YOUR FILE NAME', 'rb' )
sampleRate= f.getframerate()
channels= f.getnchannels()
format= sound.AFMT_S16_LE
snd= sound.Output( sampleRate, channels, format )
s= f.readframes( 300000 )
snd.play( s )
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