Python decorator makes function forget that it belongs to a class

Claudiu's answer is correct, but you can also cheat by getting the class name off of the self argument. This will give misleading log statements in cases of inheritance, but will tell you the class of the object whose method is being called. For example:

from functools import wraps  # use this to preserve function signatures and docstrings
def logger(func):
    @wraps(func)
    def with_logging(*args, **kwargs):
        print "Entering %s.%s" % (args[0].__class__.__name__, func.__name__)
        return func(*args, **kwargs)
    return with_logging

class C(object):
    @logger
    def f(self):
        pass

C().f()

As I said, this won't work properly in cases where you've inherited a function from a parent class; in this case you might say

class B(C):
    pass

b = B()
b.f()

and get the message Entering B.f where you actually want to get the message Entering C.f since that's the correct class. On the other hand, this might be acceptable, in which case I'd recommend this approach over Claudiu's suggestion.

Functions only become methods at runtime. That is, when you get C.f you get a bound function (and C.f.im_class is C). At the time your function is defined it is just a plain function, it is not bound to any class. This unbound and disassociated function is what is decorated by logger.

self.__class__.__name__ will give you the name of the class, but you can also use descriptors to accomplish this in a somewhat more general way. This pattern is described in a blog post on Decorators and Descriptors, and an implementation of your logger decorator in particular would look like:

class logger(object):
    def __init__(self, func):
        self.func = func
    def __get__(self, obj, type=None):
        return self.__class__(self.func.__get__(obj, type))
    def __call__(self, *args, **kw):
        print 'Entering %s' % self.func
        return self.func(*args, **kw)

class C(object):
    @logger
    def f(self, x, y):
        return x+y

C().f(1, 2)
# => Entering <bound method C.f of <__main__.C object at 0x...>>

Obviously the output can be improved (by using, for example, getattr(self.func, 'im_class', None)), but this general pattern will work for both methods and functions. However it will not work for old-style classes (but just don't use those ;)

It seems that while the class is being created, Python creates regular function objects. They only get turned into unbound method objects afterwards. Knowing that, this is the only way I could find to do what you want:

def logger(myFunc):
    def new(*args, **keyargs):
        print 'Entering %s.%s' % (myFunc.im_class.__name__, myFunc.__name__)
        return myFunc(*args, **keyargs)

    return new

class C(object):
    def f(self):
        pass
C.f = logger(C.f)
C().f()

This outputs the desired result.

If you want to wrap all the methods in a class, then you probably want to create a wrapClass function, which you could then use like this:

C = wrapClass(C)

Class functions should always take self as their first argument, so you can use that instead of im_class.

def logger(myFunc):
    def new(self, *args, **keyargs):
        print 'Entering %s.%s' % (self.__class__.__name__, myFunc.__name__)
        return myFunc(self, *args, **keyargs)

    return new 

class C(object):
    @logger
    def f(self):
        pass
C().f()

at first I wanted to use self.__name__ but that doesn't work because the instance has no name. you must use self.__class__.__name__ to get the name of the class.

As shown in Asa Ayers' answer, you don't need to access the class object. It may be worth to know that since Python 3.3, you can also use __qualname__, which gives you the fully qualified name:

>>> def logger(myFunc):
...     def new(*args, **keyargs):
...         print('Entering %s' % myFunc.__qualname__)
...         return myFunc(*args, **keyargs)
... 
...     return new
... 
>>> class C(object):
...     @logger
...     def f(self):
...         pass
... 
>>> C().f()
Entering C.f

This has the added advantage of working also in the case of nested classes, as shown in this example taken from PEP 3155:

>>> class C:
...   def f(): pass
...   class D:
...     def g(): pass
...
>>> C.__qualname__
'C'
>>> C.f.__qualname__
'C.f'
>>> C.D.__qualname__
'C.D'
>>> C.D.g.__qualname__
'C.D.g'

Notice also that in Python 3 the im_class attribute is gone, therefore if you really wish to access the class in a decorator, you need an other method. The approach I currently use involves object.__set_name__ and is detailed in my answer to "Can a Python decorator of an instance method access the class?"

You can also use new.instancemethod() to create an instance method (either bound or unbound) from a function.

Instead of injecting decorating code at definition time, when function doesn't know it's class, delay running this code until function is accessed/called. Descriptor object facilitates injecting own code late, at access/call time:

class decorated(object):
    def __init__(self, func, type_=None):
        self.func = func
        self.type = type_

    def __get__(self, obj, type_=None):
        return self.__class__(self.func.__get__(obj, type_), type_)

    def __call__(self, *args, **kwargs):
        name = '%s.%s' % (self.type.__name__, self.func.__name__)
        print('called %s with args=%s kwargs=%s' % (name, args, kwargs))
        return self.func(*args, **kwargs)

class Foo(object):
    @decorated
    def foo(self, a, b):
        pass

Now we can inspect class both at access time (__get__) and at call time (__call__). This mechanism works for plain methods as well as static|class methods:

>>> Foo().foo(1, b=2)
called Foo.foo with args=(1,) kwargs={'b': 2}

Full example at: https://github.com/aurzenligl/study/blob/master/python-robotwrap/Example4.py