Using Python, how can I multiply all matching integers in a list and then add the remaining integers

Christian Gentry 0
Viewed 67

I am working to recreate a dice game known as Knucklebones in Python as a fun personal project.

For the game logic, I need to multiply all matching values in a list and then add the remaining values.

Example 1:

numbers = [3, 3, 2]

This list should multiply both 3 and 3 together then add 2 for a total of 11.

Example 2:

numbers2 = [4, 4, 4]

This list should multiply 4 by 4 by 4 for a total of 64

Example 3:

numbers3 = [2, 4, 6]

Nothing should be multiplied in this list. All numbers should be added for a total of 12.

Can someone please help me with the logic surrounding this?

algebra logic algorithm python
2 Answers

I think this should work

I will advise to use a modified Counter from the built in module collections.

The counter by default will count just the entries of all the list them as it works similar to a dictionary is fairly simple to multiply all entries and sum them up

here you have more info:

https://docs.python.org/3/library/collections.html

https://realpython.com/python-counter/

from collections import Counter

class MyCounter(Counter):
    def __ini__(*arg, **kwargs):
        super().__init__(*arg, **kwargs)
        
    def sum_entries(self):
        total = 0
        for key, val in self.items():
            total += key**val
        return total
    
out = MyCounter([3, 3, 2])
output = out.sum_entries()

output

out = MyCounter([3, 3, 2])
output = out.sum_entries()
print(output)

11

out = MyCounter([4, 4, 4])
output = out.sum_entries()
print(output)

64

out = MyCounter([2, 4, 6])
output = out.sum_entries()
print(output)

12

EDIT

As suggested in the comments To avoid having a class if it seems to complicated

from collections import Counter

out = Counter([3, 3, 2])
total = 0
for key, val in out.items():
    total += key**val
Lucas M. Uriarte0

Built-in approach. Used dict.fromkeys to initialize to zero the counter (and remove duplicates). Then fix the frequency of the outcomes with the loop and apply the "Knucklebones" rule.

numbers = [3, 3, 2]

d = dict.fromkeys(numbers, 0)
for n in numbers:
    d[n] += 1

res = sum(k**frequency for k, frequency in d.items())
print(res)
cards0
Related