Calculate the difference between two dates in bash where date format is 08/Sep/2022

SRIVIDYA REDDY 0
Viewed 62

I have two dates in below format. I have to calculate the difference between two days in Seconds.

currentDateTime="08/Sep/2022:05:26:13"

logDateTime="07/Sep/2022:04:58:30"

diff=$(echo "$(($(date -d "$currentDateTime" +'%s')-$(date -d "$currentDateTime" +'%s')))")

echo $diff

The output is empty. Can someone help me here

awk date sed shell bash
2 Answers
$ logDateTime="07/Sep/2022:04:58:30"
$ logDateTime="${logDateTime//:*/ ${logDateTime#*:}}"
$ currentDateTime="08/Sep/2022:05:26:13"
$ currentDateTime="${currentDateTime//:*/ ${currentDateTime#*:}}"
$ let diff=($(date +%s -d "${currentDateTime//// }")-$(date +%s -d "${logDateTime//// }"))
$ echo $diff
88063
HatLess0

You need to set the date in this format: 08 Sep 2022 05:26:13 You can perform something like this:

currentDate=$(echo $currentDateTime | awk -F':' '{print $1}' | awk -F'/' '{print $1,$2,$3}')
currentTime=$(echo $currentDateTime | awk -F':' '{printf "%s:%s:%s",$2,$3,$4}')

logDate=$(echo $logDateTime | awk -F':' '{print $1}' | awk -F'/' '{print $1,$2,$3}')
logTime=$(echo $logDateTime | awk -F':' '{printf "%s:%s:%s",$2,$3,$4}')

diff=$(echo "$(($(date -d "$(echo "$currentDate $currentTime")" +'%s')-$(date -d "$(echo "$logDate $logTime")" +'%s')))")
Abhishek S0
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