What is ## in define macro?

sn01 0
Viewed 58

I used a library to work with ST microcontroller. But I have not understood this define. Does anyone know anything about it.

#define CONCAT(x, y)            x ## y
preprocessor macros c c++
2 Answers

As the name of the macro sounds it concatenates its arguments.

Here is a demonstration program.

#include <stdio.h>

#define CONCAT(x, y)            x ## y

int main( void ) 
{
    int CONCAT( my, Variable ) = 10;
    printf( "%d\n", myVariable );
}

In the program there is declared a variable with the name myVariable.

Vlad from Moscow0

As the macro name suggests, the preprocessor operator ## concatenates two tokens together.

#include <stdio.h> 

#define CONCAT(x, y)            x ## y

int main()
{
    int ab = 4;
    printf("%d\n", CONCAT(a,b));
    return 0;
}
dbush0
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