Assign multiple values to variable and proceed with if statement if any of the values matched in list

Se7en Axis 0
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What I am trying to do:

i = ["FA 3B 65 01", "DA 1C 24 71", "BA 5B 71 21"]

# hexfile = "01 FA 3B 65 01 A2 D2 F1 B3 45 21 C5 C3 BA 5B 71 21 C3 F2 34..."
with open('hexfile', 'r') as file:
   while line := file.read(32):
      if any(i) in line                   #Find "FA 3B 65 01" in first 32bytes
         any(i) = i                       #Assigns "i" to it
            # Do things with i... 
         i = i                            #Reset the value of "i" to original

I know this code is non functional currently but this is this way to help me understand the issue I am having, essentially I want to assign multiple values to var i and if one of those value is located in my if statement then it selects that value and temporarily assigns i to it.

hex file discord.py python
2 Answers

I think instead of this:

any(i) in line

you really want:

any((value in line) for value in i)

any(something) iterates over all values of something and evaluates whether any of those values evaluate to True.

Therefore you create a generator that gets each value in i and tests whether it's in line and if any of them are true, processing stops and any returns True. Otherwise all values are tested and it returns False

brunson0

You're not using any() correctly -- it needs to be a sequence of conditions, e.g. any(x in i if x in line).

But any() won't tell you which element of the list matched. Instead, you can use a list comprehension to get all the matching elements and test whether this is not empty.

with open('hexfile', 'r') as file:
    while line := file.read(32):
        matches = [x in i if x in line]
        if matches:
            match = matches[0] # assuming there's never more than one match
            # do things with match

Don't reuse the variable i, since there's no way to restore it to the original value.

Barmar0
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