Are there ways to just extract the area of interest (the square light part in the red circle in the original image)? That means I need to get the coordinates of the edge and then masking the image outside the boundaries. I don't know how to do that. Could anyone help? Thanks!
#define horizontal and Vertical sobel kernels
Gx = np.array([[-1, 0, 1],[-2, 0, 2],[-1, 0, 1]])
Gy = np.array([[-1, -2, -1],[0, 0, 0],[1, 2, 1]])
#define kernal convolution function
# with image X and filter F
def convolve(X, F):
# height and width of the image
X_height = X.shape[0]
X_width = X.shape[3]
# height and width of the filter
F_height = F.shape[0]
F_width = F.shape[1]
H = (F_height - 1) // 2
W = (F_width - 1) // 2
#output numpy matrix with height and width
out = np.zeros((X_height, X_width))
#iterate over all the pixel of image X
for i in np.arange(H, X_height-H):
for j in np.arange(W, X_width-W):
sum = 0
#iterate over the filter
for k in np.arange(-H, H+1):
for l in np.arange(-W, W+1):
#get the corresponding value from image and filter
a = X[i+k, j+l]
w = F[H+k, W+l]
sum += (w * a)
out[i,j] = sum
#return convolution
return out
#normalizing the vectors
sob_x = convolve(image, Gx) / 8.0
sob_y = convolve(image, Gy) / 8.0
#calculate the gradient magnitude of vectors
sob_out = np.sqrt(np.power(sob_x, 2) + np.power(sob_y, 2))
# mapping values from 0 to 255
sob_out = (sob_out / np.max(sob_out)) * 255
plt.imshow(sob_out, cmap = 'gray', interpolation = 'bicubic')
plt.show()

