Is there a way to find any number that has been pressed on "pygame"? and how display it?

coops 0
Viewed 38

I'm trying to ask the user the length of the code they would like to crack from 1 - 7 I also need to account for those using Numpad. Anyway, I know the code for everything except how to detect the number they have pressed.

if event.type == pygame.KEYDOWN:
    if event.key == pygame.K_2 or event.key == pygame.K_3 or event.key == pygame.K_4 or event.key == pygame.K_5 or event.key == pygame.K_6 or event.key == pygame.K_7:
        print(int(event.key)-48)
    elif event.key == pygame.K_KP_2 or event.key == pygame.K_KP_3 or event.key == pygame.K_KP_4 or event.key == pygame.K_KP_5 or event.key == pygame.K_KP_6 or event.key == pygame.K_KP_7:
        print(int(event.key)-1073741912)

This is just too clunky and even before writing this code, I thought it would be ugly to do it this way.

pygame python
3 Answers

A user friendly name of a key can be get with pygame.key.name():

for event in pygame.event.get():
    if event.type == pygame.KEYDOWN:
        print(pygame.key.name(event.key))

e.g.:

print(pygame.key.name(pygame.K_5))
print(pygame.key.name(pygame.K_KP_5))

output:

5
[5]
Rabbid760

In addition to Rabbid76's response, here is an explicit answer:

if event.type == pygame.KEYDOWN:
    if pygame.key.name(event.key) in ["2", "3", "4", "5", "6", "7"]:
        print(pygame.key.name(event.key))
    elif pygame.key.name(event.key) in ["[2]", "[3]", "[4]", "[5]", "[6]", "[7]"]:
        print(pygame.key.name(event.key))
Jobo Fernandez0

Pygame keys are just subsequent int constants, so you can use a range() like this:

if event.key in range(pygame.K_2, pygame.K_7 + 1):
    print(int(event.key) - pygame.K_0)
elif event.key in range(pygame.K_KP_2, pygame.K_KP_7 + 1):
    print(int(event.key) - pygame.K_KP_0)
hhimko0
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