replacement of prelude function minimum causes error

xsssssudjdfi 0
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I am trying to implement selection sort but I am running into an issue whenever I use my own function minim it crashes even tho that it also returns the same value as the minimum function from prelude.

rmf :: Eq t => t -> [t] -> [t]
rmf  _ [] = []
rmf oc (h : t)
      | oc  == h = t
      |otherwise = h : rmf  oc t

mymin :: Int -> Int -> Int
mymin a b
    | a > b  = b
    | a < b  = a
    | a == b = a

minim :: [Int] -> Int
minim [a]  = a
minim (h:t)  = mymin h (minim t)

seqSort :: (Eq a, Ord a) => [a] -> [a]
seqSort [] = []
seqSort xs = s : seqSort (rmf s xs)
    where s = minimum xs

main :: IO ()
main = print(seqSort [
haskell
1 Answers
minim :: [Int] -> Int

This function works on lists of integers. Not on any other lists -- only lists of integers.

seqSort :: (Eq a, Ord a) => [a] -> [a]

This function works on lists of any ordered type. On lists of integers, but also lists of booleans, of strings, etc. Hence, this function can not use minim which only works in a specific sub-case.

Solution: generalize the type of minim accordingly. You'll have to also fix mymin similarly.

As a final note, remember to post the error. Debugging this would have been much easier with the error at hand:

    * Couldn't match type `a' with `Int'
      Expected: [Int]
        Actual: [a]
      `a' is a rigid type variable bound by
        the type signature for:
          seqSort :: forall a. (Eq a, Ord a) => [a] -> [a]
        at <source>:19:1-38
    * In the first argument of `minim', namely `xs'
      In the expression: minim xs
      In an equation for `s': s = minim xs
    * Relevant bindings include
        xs :: [a] (bound at <source>:21:9)
        seqSort :: [a] -> [a] (bound at <source>:20:1)
   |
22 |     where s = minim xs
   |                     ^^

Note the part

      Expected: [Int]
        Actual: [a]

complaining that minim only accepts [Int] and won't take an [a]. That's the issue.

usernAzd0
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