Regular Expression in JavaScript with multiple conditions

Frank_G 0
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I would like to remove in javascript from my text_string all characters that are not letters (in all languages) and numbers. I can do it individually. But how can I put both in ONE expression, so that both conditions are true at the same time?

var text_string = '!#Ab+Z1_↕.2ü翻訳';
text_string = text_string.replace(/\P{Letter}/gu, ''); 
text_string = text_string.replace(/\P{Number}/gu, ''); 
text_string = text_string.replace(/[^#]/, ''); 
// should be replaced to  #AbZ12ü翻訳
regex javascript
1 Answers

You can use this regex in unicode for search:

[^\p{Letter}\p{Number}#]+

and replace with empty string.

RegEx Demo

Code:

const regex = /[^\p{Letter}\p{Number}#]+/gu;

// Alternative syntax using RegExp constructor
// const regex = new RegExp('[^\\p{Letter}\\p{Number}#]+', 'gu')

const str = `!#Ab+Z1_↕.2ü翻訳`;

const result = str.replace(regex, '');

console.log(result);

RegEx Breakup:

  • [^\p{Letter}\p{Number}#]+: In a character class match any character that is not # not a unicode letter and not a unicode number.

Remember that \p{something} is inverse of \P{something}

anubhava0
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