currently I have terms on my applications and one user can have a lot of terms registered, and my current model is like this
class Term(models.Model):
id = models.UUIDField("id", default=uuid.uuid4, editable=False, primary_key=True)
user_id = models.PositiveIntegerField("user id", default=None)
name = models.CharField()
sometimes I need to do a query to get all the users who have terms registered, so I do the following query:
Term.objects.filter(active=True)
.order_by("user_id")
.values("user_id")
.distinct()
and this is enough to solve my problems, but now I'll change my model and it will look like this:
class Term(models.Model):
id = models.UUIDField("id", default=uuid.uuid4, editable=False, primary_key=True)
user_id = models.PositiveIntegerField("user id", default=None)
name = models.CharField()
shared_with = ArrayField(models.PositiveIntegerField("id do usuario"), blank=True) # New
How you can see, I've added a new field named shared_with, that basically is a array of user ids which I want to share terms, So now I need to make a query who will return all ids who can have terms registered (shared_with included). So if i register a Term with user_id = 1 and shared_with = [2,3], my query need to return [1,2,3].
I've solved this problem today with the following code, but I think I can do this just using django ORM and one query:
users = set()
for user in (
Term.objects.filter(active=True)
.order_by("user_id")
.values("user_id")
.distinct()
):
users.add(user["user_id"])
for user in (
Term.objects.filter(active=True)
.order_by("user_id")
.values("shared_with")
):
for user_id in user["shared_with"]:
users.add(user_id)
print(users) # {1,2,3}
If someone knows how to do it and can share the knowledge, I will be grateful.