i wanted to remove all elements form list individually using list.remove(element) so, i made code:
a=[12,34,23]
for i in a:
a.remove(i)
print(a)
But I got:
[34]
Why did this happen?
python unexpected output for list operation
Viewed 30
1 Answers
It is happening because, the first time i is pointing towards the 1st element, so it removes 12, now i increases and points to the 2nd element, and the second element now is 23 and not 34, so it removes 23.
To fix this error, you can do something like:
a=[12,34,23]
for i in a:
a.remove(0)
print(a)
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