^\d{1,12}$|(?=^.{1,15}$)^\d+\.\d{1,2}$
This is the expression I currently have.
I want the max limit to be 100 000 000 000 with optional two decimals max, but if the user only adds 1 decimal, they can bump the value to 100 000 000 0001.1 if they want to.
How can I approach this issue? and is there any way to make 100 000 000 000 the max value? (Not 999 999 999 999)
^\d{1,12}$|(?=^.{1,15}$)^\d{1,12}\.\d{1,2}$
It seems the problem is the plus sign in the second part of the regex
For the part without the decimal I tried this :
^\d{1,11}$|^100000000000$|(?=^.{1,15}$)^\d+.\d{1,2}$
// works : 100000000000
// doesn't work : 999999999999
I don't know for the decimal part.
You can use the following regex to match numbers from 0 to 99999999999 with any two digits in the decimal part or 100000000000 with only zeros in the decimal part:
^(?:(?:[0-9]|[1-9][0-9]{1,11})(?:\.\d{1,2})?|10{11}(?:\.00?)?)$
See the regex demo.
^ - start of string(?: - start of a non-capturing group:
(?:[0-9]|[1-9][0-9]{1,11}) - 0 to 99999999999 number(?:\.\d{1,2})? - an optional sequence of a . char and then one or two digits| - or10{11}(?:\.00?)? - 1 and then 11 zeros optionally followed with . and one or two zeros) - end of the group$ - end of string.try this
^\d{1,12}(?:\.\d{1,2})?$
https://regex101.com/r/FcRDII/1
for the max value being 100 000 000 000, i would not validate that with regex, but if you have no other options this might work
^(?:1[0]{11}|\d{1,11})(?:\.\d{1,2})?$